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(1/5)*(5*x^2-(2*x)) = 0
(1/5)*(5*x^2-2*x) = 0
1/5*(5*x^2-2*x) = 0
5*x^2-2*x = 0
x*(5*x-2) = 0
5*x-2 = 0 // + 2
5*x = 2 // : 5
x = 2/5
x*(x-2/5) = 0
1/5*x*(x-2/5) = 0
( x-2/5 )
x-2/5 = 0 // + 2/5
x = 2/5
( x )
x = 0
x in { 2/5, 0 }
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